-16x^2+10x+6=0

Solution for -16x^2+10x+6=0 equation:

-16x^2+10x+6=0

a = -16; b = 10; c = +6;
Δ = b2-4ac
Δ = 102-4·(-16)·6
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-22}{2*-16}=\frac{-32}{-32}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+22}{2*-16}=\frac{12}{-32}
=-3/8
$